Is there a method that returns a unit vector3f that points from one vector to another?

Your question either doesnâ€™t make sense or is trivially done:

v2.subtract(v1).normalize()

Oh yeah, silly me

I have asked this same silly question before , @codex you can use linear interpolation between 2 vectors too with 1.0f scaleFactor ,the linearInterpolation equation idea comes from the slope of the straight line

## Discussion :

which indeed gets a `Vector3f`

component `V = 3 i^ + 2 j^ + 1 k^`

for example that lies between the specified 2 vectors by a scalefactor , by this equation :

how its done :

## Interpolation :

`Since , Vector0=(x0,y0,z0) , Vector1=(x1,y1,z1);`

`interPolateX = x0 + (x1-x0)*scaleFactor`

`interPolateY = y0 + (y1-y0)*scaleFactor`

`interPolateZ = z0 + (z1-z0)*scaleFactor`

```
new Vector3f(interPolateX,interPolateY,interPolateZ);
```

So , in jme :

```
Vector3f interpolatedVec=new Vector3f();
interpolatedVec.interpolateLocal(new Vector3f(0,0,0),new Vector3f(10f,5f,10f),1.0f);
```

Notice : if you flip the 2 vectors order , you will get an inversed directional vector.

## Normalizing a Vector :

if you didnâ€™t normalize your resultant vector , you will get high numbers for distant vectors , normalizing is nothing but dividing each component of Vector3f by the vector magnitude , to reach 1.0f as a resultant vector (V) & its components would represent its direction :

`||V|| = sqrt( pow(x,2) + pow(y,2) + pow(z,2)) , which is Pythagorean in nature which is the same as distance formula & Unit Circle equation`

`normalized V = V^ = ||V||/||V|| = x/||V|| + y/||V|| + z/||V|| `

So , in jme :

```
interpolatedVec.normalizeLocal();//normalize & assign the value back to this instance
```

## Conclusion :

=> Before solving any vector based problem , break down your vectors into `Vector based Components Vx , Vy , Vz`

& other operations would be `linear algebra.`

I didnâ€™t try linear Interpolation, but it should work ,

Joe asks @Pavl_G â€śdear sir, what is 1+2?â€ť, @Pavl_G answers, â€śwellâ€¦ you take the set of all rational and irrational numbers and integrate those from minus infinity to infinity over dt. Hence, e=mc2â€ť

Yep , itâ€™s an easy operation , but one better understand more why its done , I have been through this recently , so I thought sharing may help , but sometimes it seems it wonot .