Access to GUI Inputs

Troubleshooting gui
1

Hello,

I want to work with some user inputs, that means user inputs should be visible in my main java class.



I have the following classes:


  • Main.java (includes main(), simpleInitApp() and simpleUpdate())
  • InputController.java
  • controls.xml (Nifty GUI)



    I need the user inputs in main.java, so how can I access to the inputs? I already used the NiftyEventSubscriber, but I can access to user inputs only in InputController.java, but I need the inputs in main.java, where I would like to work with.



    I need access to the subscriber from the main.java, but I don’t find any solution to do that.



    How can I realise that?
2

Is your InputController a screenController on the nifty-Screen?



If so you could add a field to your InputController called “Main main”, load this controller from the screen with screen.getScreenController() and set the main-object to the new field.



After that you can direct the input-calls from your controller to the main.

1 Like
3

Thank you very much for your answer.

Yes, the InputController is a screenController on the nifty screen. But I don’t understand what you mean with “set the main-object to the new field”



Here is my small test example. In this case I want to recognize if the user has clicked on the logo, but I don’t understand what I should do now.



[xml]

<screen id=“start” controller=“package.InputController”>

<layer id=“layer” childLayout=“center”>

<image id=“imageId” filename=“Interface/nifty-logo-150x150.png”

visibleToMouse=“true” />

</layer>

</screen>

</nifty>

[/xml]



[java]

public class InputController extends AbstractAppState

implements ScreenController{

Main main;

public void bind(Nifty nifty, Screen screen) {

this.nifty = nifty;

this.screen = screen;

}



public void onStartScreen() {

}



public void onEndScreen() {

}



@NiftyEventSubscriber(id=“imageId”)

public void onClick(String id, NiftyMousePrimaryClickedEvent event){

}

}

[/java]



[java]

public class Main extends SimpleApplication{



private NiftyJmeDisplay niftyDisplay;

private Nifty nifty;



public static void main(String[] args){



Main app = new Main();

app.start();

}



public void simpleInitApp(){



niftyDisplay = new NiftyJmeDisplay(

assetManager,inputManager,audioRenderer,guiViewPort);

nifty = niftyDisplay.getNifty();

nifty.fromXml(“Interface/controls.xml”, “start”);

guiViewPort.addProcessor(niftyDisplay);

flyCam.setDragToRotate(true);

}



public void simpleUpdate(float tpf){



}



public void onEvent(String string, Object t) {

throw new UnsupportedOperationException(“Not supported yet.”);

}

}

[/java]

4

After you’ve loaded the xml-File with “.fromXml” you can fetch the screenController you’ve implemented above with “inputController = (InputController)nifty.getScreen(“screenId”).getScreenController();”



Than you can set the field main on the controller with your Application-Object (something like: “inputController.setMain(this)”)



Now your InputController is able to call the methods in your Application-Object.



Also it would be a good idea to fetch every input from your screen in your inputController. It’s not a good idea to try to delegate the input-events to other classes than a controller 'cause you will end up confused very fast.



If you follow this pattern you will always know where your input will be handled.

5

Or better yet register the screen controller with Nifty (either first using the register call or by supplying it to the from/add xml calls) and then you know what the screen controller is already.