Well the thing you probably missed was that while this vector (1,1,0) has two components that are 1 unit long, its entire length is the square root of both components squared, which is in this case about 1.41 (Sqrt(2)). When the vector is normalized this whole length is shortened to 1 and the components become shorter than 1 unit.
Starting vector: (1,1,0), length = 1.41
Normalized: (0.7,0.7,0), length = 1
Times two: (1.4,1.4,0), length = 2 (times your circle’s radius)
Ahhhhhhhhh This is what I enjoy about JME3 and the community - I learn something new every day.
Thank you both for the solution and the explanation. I understand perfectly now although I think completing the Khan Academy Geometry and Trigonometry courses would be a smart move on my part. School was a long time ago for me